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2k^2+29k-15=0
a = 2; b = 29; c = -15;
Δ = b2-4ac
Δ = 292-4·2·(-15)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-31}{2*2}=\frac{-60}{4} =-15 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+31}{2*2}=\frac{2}{4} =1/2 $
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